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Partial Fraction Decomposition

  • Thread starter PBJinx
  • Start date
  • #1
10
0
The equation i currently have is

(-7s+52)/(s^2-8s+16)

I need to convert it into a partial fraction decomposition to do a inverse Laplace Transform, but i seem to be stuck with the algebra of the what I am supposed to do.


The equation I am supposed to use to set them is

A/(s+a) + B/(s+a)^2


What i have done so far is

S^2-8s+16=A/(s-4)+B/(s-4)^2

which then brings me to

A(s-4)^2+B(s-4)=7s+52

solving for A or B being 0 will not work. must I use quadratics to solve?

i am very lost and have been at this one all day
 

Answers and Replies

  • #2
eumyang
Homework Helper
1,347
10
What i have done so far is

S^2-8s+16=A/(s-4)+B/(s-4)^2
I assume you mean this:
[tex]\frac{-7s+52}{s^2-8s+16} = \frac{A}{s-4} + \frac{B}{(s-4)^2}[/tex]

which then brings me to

A(s-4)^2+B(s-4)=7s+52
This is wrong. When you multiply both sides by s2 - 8s + 16 you should get
[tex]-7s + 52 = A(s - 4) + B[/tex]
 
  • #3
10
0
Ahh. thank you sir, got it right now
 

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