Partial fraction? or using properties?

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Homework Help Overview

The discussion revolves around solving the differential equation dx/dt = 9 - 4x^2 with the initial condition x(0) = 0. Participants are exploring integration techniques, specifically whether to use a known integral property or partial fraction decomposition.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the possibility of using a specific integral property or integrating via partial fractions after factoring the expression. There are questions about the correct application of these methods and the implications of each choice.

Discussion Status

Some participants suggest using the integral property with a u-substitution, while others confirm that partial fractions could also be a viable approach. There is ongoing exploration of the implications of these methods, and some participants are questioning the correctness of earlier steps taken in the integration process.

Contextual Notes

Participants are navigating potential mistakes in their calculations and the assumptions underlying their chosen methods. There is a focus on ensuring the correct application of mathematical properties and operations.

shseo0315
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Homework Statement



dx/dt = 9-4x^2 , x(0) = 0

when I integrate, am I supposed to use the property below?

int du / (a^2 - u^2) = 1/2a ln(u+a / u-a) + c

or

how do I integrate this by using partial fraction?

tips anyone?


Homework Equations





The Attempt at a Solution

 
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You could use that integral to solve your integral. It would require some fancy footwork, so to speak, that is, getting your value of a correct.
 
You can integrate by partial fractions if you factor 9-4*x^2. Or you can use your formula after you do the u-substitution u=2*x. Your choice.
 
Dick said:
You can integrate by partial fractions if you factor 9-4*x^2. Or you can use your formula after you do the u-substitution u=2*x. Your choice.

using the property above, I get (1/12)ln((2x+3)(2x-3)) + c = t

then, e^12t = (2x+3)(2x-3) + e^c

e^12t - e^c = (2x+3)(2x-3)

here how can I go further to have x equals to whatever.

thanks a lot. it really helps.
 
shseo0315 said:
using the property above, I get (1/12)ln((2x+3)(2x-3)) + c = t

then, e^12t = (2x+3)(2x-3) + e^c

e^12t - e^c = (2x+3)(2x-3)

here how can I go further to have x equals to whatever.

thanks a lot. it really helps.

You've got two mistakes there. i) Shouldn't it be (2x+3)/(2x-3)? Not the product? And worse, ii) When you exponentiate e^(A+c) you get (e^A)*(e^c), not e^A+e^c. Do you see where you did that?
 

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