1. The problem statement, all variables and given/known data What is the probability, P, of locating a particle between x = 0 (the left-hand end of a box) and x = 0.2 nm in its lowest energy state in a box of length 1.0 nm? 2. Relevant equations Probability = ∫ψ2dx ψ = (2/L)1/2sin(n∏x) 3. The attempt at a solution ψ2 = (2/L)sin2(n∏x) ∫(2/L)sin2(n∏x)dx = 2/L [x/2 - (L/n∏x)sin(2n∏x/L)] from x = 0 to x = 0.2 I plugged in the numbers n=1 and L = 1 and got about 0.2. The answer is 0.05.