Particle in a magnetic field - x,y,z components

AI Thread Summary
A particle with a charge of 2.8 C is moving through a uniform magnetic field, with its velocity given as (1.4 i + 1.2 j + 0.48 k) m/s and a magnetic force of (11.9 i - 14.1 j + 1.57 k) N. The x and y components of the magnetic field are equal, and the relationship between force, charge, velocity, and magnetic field is described by the equation F = q(v x B). To find the magnetic field components, one must equate the components of the calculated magnetic force with the given force. This requires determining the vector cross product of velocity and magnetic field in component form.
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Homework Statement



A particle with charge 2.8 C moves through a uniform magnetic field. At one instant the velocity of the particle is (1.4 i + 1.2 j + 0.48 k) m/s and the magnetic force on the particle is (11.9 i - 14.1 j + 1.57 k) N. The x and y components of the magnetic field are equal. What are (a) the x-component, (b) the y-component, and (c) the z-component of the magnetic field?


Homework Equations



F=q(v X B)

The Attempt at a Solution



I have tried this twice and cannot figure out this solutions. Can someone please point be in the right direction?
 
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If the vector B is B=Bxi+Byj+Bzk

What is q(vxB) equal to? (Write this in the vector form)

Since they gave you what F is, and you just calculated q(vxB) (which is F), equate components.
 

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