- #1
maggie56
- 30
- 0
I don't understand how to find particle paths, for example i have a question that states;
u= (-z + cos(at)) j + (y + sin(at)) k
for the complementary function
y' = -z
x' = y
so y''=-y therefore y = A cos t + B sin t and z = A sin t - B cos t
Now for the particular integral, i know the answer is
y=1/(a-1) sin (at) and z = -1/(a-1) cos (at)
i assume this has been found using a linear combination of cos at and sin at but i don't see how
Could someone please help
Thanks
u= (-z + cos(at)) j + (y + sin(at)) k
for the complementary function
y' = -z
x' = y
so y''=-y therefore y = A cos t + B sin t and z = A sin t - B cos t
Now for the particular integral, i know the answer is
y=1/(a-1) sin (at) and z = -1/(a-1) cos (at)
i assume this has been found using a linear combination of cos at and sin at but i don't see how
Could someone please help
Thanks