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Particle physics problem

  1. Feb 5, 2008 #1
    1. The problem statement, all variables and given/known data

    In the following reaction, the incident Kaon has kinetic energy of 1.63GeV.Calculate the total energy to be divided between the four recoiling particles.

    [tex]\bar{K}^-\ + [/tex][tex]\ p ^+ [/tex] [tex]\rightarrow[/tex][tex]\Sigma^-\ + [/tex] [tex]\pi^+\ + [/tex][tex]\pi^-\ + [/tex][tex]\pi^+[/tex]

    Given Given mass energy of pi meson=139.6MeV, [tex]\Sigma[/tex]=1197.3MeV, proton=938.3MeV and kaon=493.8 MeV

    2. Relevant equations
    3. The attempt at a solution

    Using conservation of energy straightway, we get

    493.8+938.3+1630=(3x139.6)+3(T_pi)+1197.3+(T_Sigma)
    This gives, 3(T_pi)+(T_sigma)=1446

    Now,it appears that we are to use conservation of momentum;but I am having difficulty in finding out the appropriate equation.Since, the particles are charged, they might move in the opposite direction.

    Can anyone please help?
     
    Last edited: Feb 6, 2008
  2. jcsd
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