(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

In the following reaction, the incident Kaon has kinetic energy of 1.63GeV.Calculate the total energy to be divided between the four recoiling particles.

[tex]\bar{K}^-\ + [/tex][tex]\ p ^+ [/tex] [tex]\rightarrow[/tex][tex]\Sigma^-\ + [/tex] [tex]\pi^+\ + [/tex][tex]\pi^-\ + [/tex][tex]\pi^+[/tex]

Given Given mass energy of pi meson=139.6MeV, [tex]\Sigma[/tex]=1197.3MeV, proton=938.3MeV and kaon=493.8 MeV

2. Relevant equations

3. The attempt at a solution

Using conservation of energy straightway, we get

493.8+938.3+1630=(3x139.6)+3(T_pi)+1197.3+(T_Sigma)

This gives, 3(T_pi)+(T_sigma)=1446

Now,it appears that we are to use conservation of momentum;but I am having difficulty in finding out the appropriate equation.Since, the particles are charged, they might move in the opposite direction.

Can anyone please help?

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# Homework Help: Particle physics problem

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