Particles connected with a string

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Two particles of mass m are connected by a light string and positioned on a frictionless surface, with a midpoint being pulled upwards by a force F. As the midpoint is lifted, the particles move closer together, and the problem involves calculating their acceleration when the separation is 2x. The initial approach uses tension T and the sine of the angle θ to find acceleration, but the correct expression involves the tangent of θ instead. The discussion highlights a misunderstanding of the net force acting on the particles, emphasizing that the motion occurs along the plane towards each other, not solely due to tension. Clarification on the net force and correct application of trigonometric relationships is needed to resolve the confusion.
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Homework Statement



Two particle of mass m each are tied at the ends of a light string of length 2a. The whole system is kept on a frictionless horizontal surface with the string held tight so that each mass is at a distance ‘a’ from the center P (as shown in the figure). Now, the mid-point of the string is pulled vertically upwards with a small but constant force F. As a result, the particles move towards each other on the surface. The magnitude of acceleration, when the separation between them becomes 2x is
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Homework Equations

The Attempt at a Solution


http://2.bp.blogspot.com/_lRKubY9oOyI/RrGGAxqjRUI/AAAAAAAAAHQ/TtdYi47lpDc/s1600-h/Newton

2Tsinθ = F
T = F/2sinθ
where sinθ = (a2 - x2)1/2 / a
Net force on each particle is T.
So T = maacceleration
So, aacceleration = F/2msinθ

However, the answer is F/2mtanθ. I don't get why. Please help?
 
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erisedk said:
Net force on each particle is T.
So T = maacceleration
So, aacceleration = F/2msinθ

Draw a free body diagram of the mass- do you get the net force on it to be T? you are making some serious error-the motion is along the plane towards the other body so net force can not be T.
 
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