Partition function & Boltzman, Maxwell distri

AI Thread Summary
The discussion explores the relationship between the partition function and the Maxwell-Boltzmann (MB) distribution, noting that both involve exponentials of negative energy but differ in focus. The MB distribution pertains specifically to the velocities and positions of particles, while the partition function encompasses broader macro variables like energy, pressure, and temperature. It highlights that the normalization constant for energy probability distributions is derived from the partition function. The MB distribution can be seen as a specialized case within the broader context of the partition function, which can also accommodate systems with potential energy. Overall, the partition function provides a more general framework for statistical mechanics than the MB distribution.
pivoxa15
Messages
2,250
Reaction score
1
What is the relation between the partition function and the Boltzman, Maxwell distribution?

Differences and similarities?

Both have exponentials to the power of the negative total energy of the microstate. Although the word microstate dosen't occur in the Boltzman, Maxwell case.

Is the BM distribution about velocity and position of particles only whereas the partition function is about any distribution involving macro variables? So it cannot calculate the speeds and position of particles in the system but can tell you about energy, pressure, temperture etc.
 
Last edited:
Physics news on Phys.org
The normalization constant of the energy probability distribution of a system is one over the partition function.

In the MB distribution, the system is a single particle in the heat bath of all the rest. The microstates are that particle at different energies (kinetic + potential if any).
 
Last edited:
So the MB is a more specialised or more restricted entity? Could you use the partition function to calculate position and velocity of particles?
 
Interesting but you can't derive the partition function from the MB?

If you had non gas with potential energy than you would replace E=p^2/(2m) with K+U?

Then you would get the more general MB disbribution.
 
Thread 'Motional EMF in Faraday disc, co-rotating magnet axial mean flux'
So here is the motional EMF formula. Now I understand the standard Faraday paradox that an axis symmetric field source (like a speaker motor ring magnet) has a magnetic field that is frame invariant under rotation around axis of symmetry. The field is static whether you rotate the magnet or not. So far so good. What puzzles me is this , there is a term average magnetic flux or "azimuthal mean" , this term describes the average magnetic field through the area swept by the rotating Faraday...
It may be shown from the equations of electromagnetism, by James Clerk Maxwell in the 1860’s, that the speed of light in the vacuum of free space is related to electric permittivity (ϵ) and magnetic permeability (μ) by the equation: c=1/√( μ ϵ ) . This value is a constant for the vacuum of free space and is independent of the motion of the observer. It was this fact, in part, that led Albert Einstein to Special Relativity.
Back
Top