Path difference in Fabry-Perot etalon

AI Thread Summary
The discussion focuses on understanding the path difference in a Fabry-Perot etalon, particularly in relation to an experiment on the Zeeman effect. The user questions the equation for path difference, suggesting it should be \Delta l = 2t/\cos{\theta}, while others clarify that the correct formula is \Delta l = 2t \cos{\theta}. This discrepancy arises from considering both the optical path difference (OPD) inside the resonator and the OPD outside, which must be accounted for. The conversation emphasizes the importance of accurately calculating these path differences for precise experimental outcomes. Overall, the clarification of the path difference is crucial for understanding the functioning of the Fabry-Perot etalon in optical experiments.
hadoque
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Hi
I'm trying to understand how the Fabry-Perot etalon works for an experiment regarding the Zeeman effect.
Looking at the image could anyone tell me why the path difference in the etalon is \Delta l = 2t \cos{\theta}? In my head, the path difference is \Delta l = 2t/\cos{\theta}, in other words, just the length of two more reflections.
 

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Wow, I posted that question two years ago. Thanks for taking the time to answer it though.. :)
 

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