Path Integral of F = (x, y2, 2z) from a to b - Calculating Line Integrals

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Homework Statement


For F = (x, y2, 2z), evaluate the path integrals along the line of a to b:

\vec{a}=(0,0,0), \vec{b}=(1,1,1), \int^{b}_{a} \vec{F} \times d\vec{r}

\int^{b}_{a} \vec{F} ds

Homework Equations



No idea.

The Attempt at a Solution



I don't have a clue what these integrals even evaluate to. The first one should be a vector, and I have no idea what that even means, an integral that isn't a scalar. The second one is the same problem.
 
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Write down the path r(s)=(s,s,s) from (0,0,0) to (1,1,1) with s going from 0 to 1. dr is (dr/ds)*ds which is (1,1,1)*ds. The integral of Fds is F(r(s))*ds. To integrate the vector ds just find the vector whose components are the integral of each component of the vector. I.e. (integral sds, integral s^2ds, integral 2sds). To find Fxdr cross the vector F(r(s)) with (1,1,1) and integrate that vector ds.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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