Path Integrals Harmonic Oscillator

[Wislan]

Hi,

I am reading through the book "Quantum Mechanics and Path Integrals" by Feynman and Hibbs and am having a bit of trouble with problem 3-12. The question is (all Planck constants are the reduced Planck constant and all integrals are from -infinity to infinity):
The wavefunction for a harmonic oscillator is (at t=0): ψ(x,0) = exp[-$\frac{mω}{2h}$ (x-a)$^{2}$]
then, using Eq.(3.42) (ψ(x$_{b}$,t$_{b}$)=∫K(x$_{b}$,t$_{b}$;x$_{c}$,t$_{c}$) * ψ(x$_{c}$,t$_{c}$) dx$_{c}$) and the results of problem 3-8 (the Kernel for a harmonic oscillator K=($\frac{mω}{2πihsin(ωτ)}$)$^{1/2}$ * exp[$\frac{imω}{2hsin(ωτ)}$((x$_{b}$$^{2}$ + x$_{a}$$^{2}$)cos(ωτ)-2x$_{b}$x$_{a}$)]
show that
ψ(x,τ)=exp[-$\frac{iωτ}{2}$-$\frac{mω}{2h}$(x$^{2}$-2axe$^{-iωτ}$+a$^{2}$cos(ωτ)e$^{-iωτ}$)]

Now so far as I can tell, a solution is to multiply the wavefunction at time 0 by the kernel from x at t=0 to x at t=τ and then integrate over all x, however (unless I've made an algebra mistake which is always possible) this doesn't give the required answer. Any ideas?

Thanks,
Will

 

[fzero]

Yes, the evolution of the wavefunction is given by

$$ \psi(x,t) = \int_{-\infty}^\infty K(x,t;x',0) \psi(x',0) dx'.$$

This integral is of the form

$$ \begin{split}
\int_{-\infty}^\infty \exp{\left[ -A (x')^2 + B x' + C\right]} dx' &= \int_{-\infty}^\infty\exp{\left[ -A \left(x'-\frac{B}{2A}\right)^2 + C + \frac{B^2}{4A} \right]} dx'\\
& = \sqrt{\frac{\pi}{A}} \exp{\left[ C + \frac{B^2}{4A} \right]}. \end{split}$$

Hopefully some of this is familiar and you can figure out the algebra.