Pendulum in Water: Period and Resistance

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A simple pendulum's period is influenced by gravitational acceleration (g), which differs on the moon, leading to a longer period than on Earth. The pendulum would not swing indefinitely on the moon due to the lack of air resistance, but its period can be calculated using the formula T=2π√(1/g). When swinging in water, the pendulum experiences greater resistance than in air, resulting in a shorter time to come to a complete stop. The graph of period against length for a pendulum in water is expected to have a lower gradient compared to that in air, indicating a different relationship due to increased resistance. Understanding these principles is crucial for accurate coursework completion.
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Homework Statement



first question: If a simple pendulum with a period of 1 second is set in motion on the moon,determine the new period of this pendulum.

second question: If a pendulum is made to swing in water,compare the time taken for this pendulum to come to a complete stop with the time taken by a pendulum swinging in air. Explain the difference.

Homework Equations



T=2(3.142)x(1/g)^1/2

The Attempt at a Solution



first question: the pendulum will swing forever on the moon because it is in a vacuum rite? but what does it mean by determine the new period?
the graph of period Ts against length for this question will be a straight line parallel to the x axis..?

second question: if a pendulum is made to swing in water, the resistance is higher compare to air rite? so the time taken for a pendulum to come to a complete stop is shorter compare to a pendulum swinging in the air...so the answer should be resistance?
but what is the graph of pendulum in water (period against length) would be like? is it a curve? have a lower gradient compare to the graph of pendulum in air?

i just want to make sure i did right for my coursework. thanks for your help.
 
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The period depends on g. g is different on the moon. Hence the period will be different.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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