- #1
Trekky0623
- 6
- 0
The string in the Figure is L = 118.0 cm long and the distance d to the fixed peg P is 99.1 cm. When the ball is released from rest in the position shown, it will swing along the dashed arc. How fast will it be going when it reaches the lowest point in its swing? What about the highest in its circular arc?
Relevant equations
PE = m * g * h
KE = (1/2)m * v2
Attempt
PE = m * g * h
PE = m * 9.8 m/s2 * .118 m
PE = KEBOTTOM = (1/2)m * v2
v2 = ((m * 9.8 m/s2 * .118 m)/((1/2)*m)))
v2 = ((9.8 m/s2 * .118 m)/(1/2))
v2 = 2 * 9.8 m/s2 * .118 m
v = SQRT(2 * 9.8 m/s2 * .118 m)
v = 1.52 m/s
I've only done this first part. I got 1.52 m/s, but the computer says I'm wrong. I was wondering if anyone could spot a problem in my equations.
Relevant equations
PE = m * g * h
KE = (1/2)m * v2
Attempt
PE = m * g * h
PE = m * 9.8 m/s2 * .118 m
PE = KEBOTTOM = (1/2)m * v2
v2 = ((m * 9.8 m/s2 * .118 m)/((1/2)*m)))
v2 = ((9.8 m/s2 * .118 m)/(1/2))
v2 = 2 * 9.8 m/s2 * .118 m
v = SQRT(2 * 9.8 m/s2 * .118 m)
v = 1.52 m/s
I've only done this first part. I got 1.52 m/s, but the computer says I'm wrong. I was wondering if anyone could spot a problem in my equations.
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