Percent increase/decrease cylinder (no values)

[riskybeats]

By approximately what percent would the volume of a right circular cylinder increase or decrease if the height were to increase by 2% and the radius of the base were to decrease by 1.5%?

Partial differentials makes sense in this case, I am just stuck when I have no usable values.

Volume of a cylinder = \pir²h
dV = \pir²dh + 2\pir dr

dh = 1.02
dr = .985

I'm stuck in how to translate this in a comparable way to the original cylinder. Any suggestions are welcome!

 

[rock.freak667]

Recheck your expression for dV.

When you do that divide the left side by V and the right side by πr²h and then you can find the percentage.

 

[Dick]

No, no. dh isn't 1.02, dh/h is 0.02. And the quantity you want to find is the percentage change. That's dV/V.

 

[riskybeats]

Okay, the only reason I did 1.02 is because I thought of doing I could express is as a negative/positive percentage. This was obviously a bad move and doesn't make any sense. But I got it now. Thanks for the help everyone!