Period and amplitude of oscillations.

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SUMMARY

The discussion focuses on calculating the period and amplitude of oscillations for two blocks involved in an inelastic collision. Block "A" with a mass of 2 kg and an initial velocity of 10 m/s collides with block "B," also 2 kg, on a frictionless surface. The spring constants are 100 N/m and 300 N/m. The user initially attempted to equate initial and final energies but encountered difficulties, later realizing the need to first apply conservation of momentum to find the final velocity before determining the amplitude of oscillations.

PREREQUISITES
  • Understanding of conservation of momentum
  • Familiarity with energy conservation principles in oscillatory systems
  • Knowledge of spring constants and their role in oscillations
  • Basic algebra for solving quadratic equations
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  • Learn how to derive the amplitude of oscillations from energy conservation equations
  • Explore the relationship between spring constants and oscillation frequency
  • Investigate the effects of mass on the period of oscillations in spring-mass systems
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Students studying physics, particularly those focusing on mechanics and oscillatory motion, as well as educators looking for practical examples of energy conservation and momentum in collisions.

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Homework Statement


Block “A” is released with initial velocity v=10 m/s. Find the period and the amplitude
of oscillations after inelastic collision of block “A” with block “B”. The mass of block “A” is
2 kg, the mass of block “B” is 2 kg. The spring constants of the springs are 100 N/m and 300
N/m. The surface is frictionless and the springs are massless.

Homework Equations


E_i = \frac {1}{2} m_A v^2
E_f = \frac {1}{2} k A^2 + \frac {1}{2} (m_A + m_B) v^2

The Attempt at a Solution



I attached the image of the problem at the bottom.

Trying to find the amplitude of oscillations... I tried E_i = E_f.

\frac {1}{2} m_A v^2 = \frac {1}{2} k A^2 + \frac {1}{2} (m_A + m_B) v^2
200 = 400A^2 + 400

Got stuck here, because when I subtract 400 I get -200 on the left side and I can't take the square root... am I setting this up right?
 

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  • spring problem.png
    spring problem.png
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Never mind, I figured out what I was doing wrong.

First you consider the initial and final momentum...
p_i = p_f
m_A v_i = (m_A + m_B)v_f

Solve for v_f...

Then \frac {1}{2} kA^2 = \frac {1}{2} (m_A + m_B) v^2.
 

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