Period of a Proton's Orbit arount magnetic field

AI Thread Summary
A proton moving perpendicular to a magnetic field of 0.005 T requires understanding the relationship between magnetic force and centripetal force to determine its orbital period. The magnetic force acting on the proton is equivalent to the centripetal force necessary for circular motion, represented by the equation FB = mv²/r. To find the period, the correct approach involves using the relationship v/r, allowing the cancellation of variables without needing the radius explicitly. The discussion emphasizes the importance of recognizing that the magnetic force is the sole force acting on the proton in this scenario. Understanding these concepts is crucial for solving problems involving charged particles in magnetic fields.
Chase11
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Homework Statement


A proton moves perpendicular to a magnetic field of .005 T. What is the period of the proton's circular orbit?

Homework Equations


1. T=2pi/v
2. FB=qv x B

The Attempt at a Solution


I know I need to solve for velocity first so I can use the period equation, but I don't understand how I can do that without being given the force. If I knew the force, I could solve for v using equation 2 and then plug that value into equation 1 to find the period.
 
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What is the period of the proton's circular orbit?
What sort of force is associated with circular motion?
(note: eq. 1 is incorrect.)
 
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I always thought it was gravitational force, but I have never done a problem in which I need to find the period of a proton moving around a magnetic field. I can't find any other equations that I can use for the period, as I don't have enough information. Is gravitational force what you are referring to?
 
Okay so are you saying that I need to solve for the centripetal force, and that will be the force that I use in my equation 2? I'm still confused though, because the centripetal force formula requires me to know the velocity and the radius. I see why it would be a centripetal force, I just don't understand how I would be able to solve for that with the information I am given.
 
How many forces are on the proton?
 
I honestly thought it was just the magnetic force, we've never done anything where I needed to know anything other than the magnetic field, velocity, and charge. Does gravity act as a force on a proton? And then you said it is like a centripetal force.
 
The centripetal force applies to circular motion - lots of things go in circles: not just planets.
In this case, the magnetic force is to the proton what gravity is to the planet.

There is one force on the proton: that is the magnetic force.
Because this force makes the proton go in a circle, that force is also the centripetal force.
So how od you write that out mathematically?
 
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FB=qv x B= mv2/r

Is that right? I would still need the radius to be able to solve this.
 
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Keep going, maybe it cancels at some moment...

Remember
Simon Bridge said:
(note: eq. 1 is incorrect.)
 
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I got it thanks.
 
  • #12
Chase11 said:
FB=qv x B= mv2/r

Is that right?
Yes.
I would still need the radius to be able to solve this.
No you don't.
You don't know v or r, but you do know v/r (see the correct equation 1).
 
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