Period of Small Amplitude Oscillation for Hoop of Radius 50cm

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The discussion focuses on calculating the period of small amplitude oscillation for a circular hoop with a radius of 50 cm. The formula T = 2π(I/(MgD))^0.5 is provided, but the user is uncertain about how to proceed without the mass (M) of the hoop and rod. Key points include the need to determine the moment of inertia for both the hoop and the rod, as well as the distance (D) from the center of mass to the pivot point. Clarification is sought on whether the rod is rotating and how to find its length if not provided. Understanding these factors is essential for accurately calculating the oscillation period.
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Homework Statement


"A circular hoop of radiusm 50 cm is hung on a narrow horizontal rod and allowed to swing in the plane of the hoop. What is the period of its oscillation, assuming that the amplitude is small?

Homework Equations



T= 2*pi(I/(MgD))^.5

The Attempt at a Solution



Ok... so if M is not given for the hoop and the rod, how do I go about figured it out? What is the value of D? And do I factor the moment of inertia for both the rod and hoop, and if so... how do I figure out the length of the rod, if it is not given.

Thanks.
 
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Find the moment of inertia- it will have a factor of M in it.
I believe D is the distance from the center of mass to the pivot point.
Is the rod rotating?
 
robb_ said:
Find the moment of inertia- it will have a factor of M in it.
I believe D is the distance from the center of mass to the pivot point.
Is the rod rotating?

Yes.. it is swinging from the hoop
 

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