Perpendicular Bisector & Altitude of Triangle: A(4;2) B(11;6) C(-3;-1)

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The discussion focuses on finding the equations of the perpendicular bisector of side a and the altitude of side c for triangle ABC with vertices A(4,2), B(11,6), and C(-3,-1). The proposed equation for the perpendicular bisector of side a is -7x + 14y = 7, while the altitude of side c is suggested to be -4x + 7y = 5. Participants clarify the definition of side a, indicating it is typically the side opposite angle A. Additionally, there is a request for guidance on how to find the intersection of the two lines. The conversation emphasizes the need for clear problem-solving steps in geometry.
adod
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The vertices of a triangle are A(4;2) ; B(11;6) ; C(-3;-1)
What is the equation of the perpendicular bisector of side a?
(i think -7x+14y=7)
What is the equation of the altitude of side c?
(i think -4x+7y=5)
What is the intersection of the previous lines?
i have no idea about this,please help,and also write down how you solved it
 
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adod said:
The vertices of a triangle are A(4;2) ; B(11;6) ; C(-3;-1)
What is the equation of the perpendicular bisector of side a?
(i think -7x+14y=7)
What is the equation of the altitude of side c?
(i think -4x+7y=5)
What is the intersection of the previous lines?
i have no idea about this,please help,and also write down how you solved it

Welcome to PH (=
what is side a? AB? AC ? BC?
 
Side a is usually the side across from angle A.

How does one normally find the point of intersection of two lines?
 

Thread 'Family of lines that are at a distance of 5 from the origin'

I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
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