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Perpendicular vector in 6th dimensional space

  1. Apr 17, 2012 #1
    I am working on a software for analysis of brain connections using MRI.

    Please suggest the simplest way to find a vector which is:

    perpendicular to a unit vector that is positioned in the coordinate center,

    it should be in the 2D plane containing the given vector and a given point on the unit 5-sphere.

    Everything takes place in 6 dimensional Euclidean space.
     
  2. jcsd
  3. Apr 18, 2012 #2

    Fredrik

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    This should work:

    Denote the two given unit vectors by u and v. First we find an orthonormal basis {f,g} for the 2-dimensional subspace spanned by {u,v}. Define g=v. The orthogonal projection of u onto the 1-dimensional subspace spanned by g is <g,u>g. Let's denote this vector by p. The vector u-p will be orthogonal to g. So we define ##f=(u-p)/\|u-p\|##.

    Now we can write u=af+bg, where a=<f,u> and b=<g,u>. Define w=bf-ag. This w is orthogonal to u.
     
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