Final Temp of Water in Calorimeter After Heating Silver Ring

AI Thread Summary
The discussion revolves around calculating the final temperature of a silver ring and water system, considering energy transfer to the surroundings. The silver ring, weighing 25.5 grams and initially at 84 degrees Celsius, is placed in a calorimeter with 0.05 kg of water at 24 degrees Celsius. The calorimeter loses 0.140 kJ of energy to the environment before reaching thermal equilibrium. The participants initially express confusion about applying conservation of energy principles but ultimately resolve the problem independently. The focus remains on understanding the heat transfer without phase changes involved.
laker88116
Messages
57
Reaction score
0
A 25.5 gram silver ring ( c=234 J/kg * c) is heated to a temperature of 84 degrees C and then placed in a calorimeter containing 0.05 kg of water at 24 degrees C. The calorimeter is not perfectly insulated and .140 kJ of energy is transferred to the surrounding before a final temperature is reached. What is the final temperature?

Ok, I was thinking that there is no phase change so I am not sure is it just conservation of energy, and if so, how do I start?
 
Physics news on Phys.org
Nevermind, I was able to figure it out.
 
So I know that electrons are fundamental, there's no 'material' that makes them up, it's like talking about a colour itself rather than a car or a flower. Now protons and neutrons and quarks and whatever other stuff is there fundamentally, I want someone to kind of teach me these, I have a lot of questions that books might not give the answer in the way I understand. Thanks
Back
Top