Phase of Simple Harmonic Motion: Determining the Phase at a Specific Time

AI Thread Summary
The discussion focuses on determining the phase of a body oscillating in simple harmonic motion, described by the equation x = 5sin(pi*t + pi/3). At t = 2 seconds, the phase is calculated by evaluating the expression inside the sine function, resulting in 7pi/3 radians. Participants clarify that the phase angle corresponds to the value in the brackets of the sine function, which represents the angle on a unit circle. The understanding of phase in relation to simple harmonic motion is reinforced, emphasizing its geometric interpretation. The final consensus confirms that the phase at t = 2s is indeed 7pi/3 radians.
sugz
Messages
110
Reaction score
0

Homework Statement


A body oscillates with simple harmonic motion along the x-axis. Its displacement varies with time according to the equation x = 5sin(pi*t + pi/3). The phase (in rad) of the motion at t = 2s is

a) (7pi)/3 b) pi/3 c) pi d) (5pi)/3 e) 2pi

Homework Equations

The Attempt at a Solution


I plugged in the value for t=2 but I really did not know how to past this point. The answer is supposed to be a)
 
Physics news on Phys.org
sugz said:

Homework Statement


A body oscillates with simple harmonic motion along the x-axis. Its displacement varies with time according to the equation x = 5sin(pi*t + pi/3). The phase (in rad) of the motion at t = 2s is

a) (7pi)/3 b) pi/3 c) pi d) (5pi)/3 e) 2pi

Homework Equations

The Attempt at a Solution


I plugged in the value for t=2 but I really did not know how to past this point. The answer is supposed to be a)

Please show your work. What do you get for x(2)?
 
x(2) = 4.33. But how do I determine the phase? Is the phase simply what is in the brackets? So the phase is equal to 2pi+(pi/3)?
 
sugz said:
So the phase is equal to 2pi+(pi/3)?

Yes. What is that in radians?
 
Its 7pi/3. So for any equation of a particle in SHM, the phase is the part inside the brackets?
 
sugz said:
Its 7pi/3. So for any equation of a particle in SHM, the phase is the part inside the brackets?

Sort of. For a sinusoidal function (sin or cos), you can picture the value in 2-dimensions on a circle. The amplitude is the radius of the circle, and the point that rotates around the circle with time has some phase angle θ with the positive horizontal axis. If you have a sin() function like you do in this problem, then yes, the value in the () is the phase angle θ with the horizontal axis.

http://images.tutorcircle.com/cms/images/106/unit-circle-example.png
 

Attachments

  • unit-circle-example.jpg
    unit-circle-example.jpg
    7.3 KB · Views: 667
Now I understand, thank you so much!
 
It may be true in general, but sometimes we define phase with respect to something, so I'm not sure it is a general statement. Others can correct that if appropriate. :smile:
 

Similar threads

Replies
5
Views
2K
Replies
1
Views
2K
Replies
6
Views
4K
Replies
3
Views
597
Replies
2
Views
1K
Replies
10
Views
2K
Back
Top