Phase Power Calculation: Determining Total Power Input into System

AI Thread Summary
To calculate the total power input into the system for phases A, B, and C, the initial calculations did not account for phase angles, resulting in volt-amps instead of watts. After considering the phase angles using the formula P=VIcos(θv-θi), the corrected power values are approximately 796.75 W for phase A, 842.64 W for phase B, and 789.28 W for phase C, leading to a total power of about 2428.67 W. The discussion highlights the importance of including phase angles in AC power calculations. Additionally, there is a query regarding the nature of the load being analyzed. Accurate power calculations are essential for effective system analysis.
TurboST2
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Homework Statement


I need to calculate the power for phase A, B, and C so that I can determine the total power into the system.

I have measured the following data:
VA magnitude = 117.7 [v]
VA angle = 0°
IA magnitude = 7.5 [A]
IA angle = -25.5°
VB magnitude = 117.7 [v]
VB angle = -124.1°
IB magnitude = 7.7 [A]
IB angle = -145.7°
VC magnitude = 117.2 [v]
VC angle = 117.5°
IC magnitude = 7.3 [A]
IC angle = 94.8°

Homework Equations


P=IV

The Attempt at a Solution


Does this mean?:
Phase A power = 882.75 [w]
Phase B power = 906.29 [w]
Phase C power = 855.56 [w]

Total power into system = 2644.6 [w]
 
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Hi TurboST2 :welcome:

So you didn't take phase angle into account? That means you've calculated volt-amps for each phase, not watts.

Does your textbook show a formula for AC power?
 
Thank you for the helpful reply. No I did not take the phase angle into account. I wasn't sure if this was necessary for calculating power in this way.

Taking the angle into account would I use this equation instead? P=VIcos(θv-θi) giving the following results:

Pa = 796.75 [w]
Pb = 842.64 [w]
Pc = 789.28 [w]

Ptotal = 2428.67 [w]
 
If you showed the data you used in arriving at those new numbers, it would be easy to judge whether you are on the right track.

What is the nature of your load here?
 
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