Phenol Dissociation: O-H Bond Weaker?

Click For Summary
SUMMARY

The discussion centers on the dissociation of phenol and the impact of resonance on the O-H bond strength. It is established that the delocalization of the oxygen's electrons into the benzene ring reduces the O-H bond strength, facilitating proton release. The resonance structures of phenol illustrate that the oxygen can carry a positive charge, promoting proton dissociation, while the phenolate ion shows negative charge delocalization across the carbon atoms in the ring. This delocalization is crucial for understanding the acidity of phenol.

PREREQUISITES
  • Understanding of resonance structures in organic chemistry
  • Knowledge of phenol and phenolate ion properties
  • Familiarity with electron delocalization concepts
  • Basic grasp of acid-base chemistry
NEXT STEPS
  • Study resonance structures of phenol and phenolate ion
  • Explore the concept of electron delocalization in aromatic compounds
  • Investigate the acidity of phenols compared to aliphatic alcohols
  • Learn about the effects of substituents on phenol acidity
USEFUL FOR

Chemistry students, organic chemists, and educators seeking to deepen their understanding of phenol's acidity and resonance effects.

crays
Messages
160
Reaction score
0
Hi, my teacher told me that the oxygen in phenol would be delocalized into the benzene ring's electron and thus, making the O-H bond weaker, thus easing the release of the H proton. But i would like to know, since a benzene consist of 3 double bonds, shouldn't the electrons from the benzene itself already occupied most of the shield, thus making it harder for any other electrons to be joined in? Wouldn't the Oxygen, O's electron be repel if they try to merge into the benzene's electron cloud?
 
Physics news on Phys.org
Try drawing resonance structures for phenol. You'll see that in some of them, the oxygen will have a positive charge and thus want to get rid of its proton. Alternatively, if you draw resonance structures for the phenolate ion, you should see that the negative charge from the oxygen gets delocalized to carbons on the ring.
 

Similar threads

  • · Replies 0 ·
Replies
0
Views
2K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
8K
  • · Replies 7 ·
Replies
7
Views
17K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 1 ·
Replies
1
Views
4K