Photoelectric Effect and stopping potential

AI Thread Summary
The discussion revolves around calculating the stopping potential for different wavelengths of light striking a metal surface, specifically 445 nm and 410 nm. It is noted that the stopping potential for 445 nm light is 70% of that for 410 nm light, leading to the equation relating their energies. The work function of the metal is a crucial factor in determining the stopping potential, which was initially overlooked. The calculated work function is determined to be 2.23 eV, identifying the metal as potassium. The conversation emphasizes the importance of including the work function in the calculations for accurate results.
Turion
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Homework Statement



When 445 nm light strikes a certain metal surface, the stopping potential is 70% of that which results when 410 nm light strikes the same metal.

Homework Equations





The Attempt at a Solution



$$P=0.7P'\\ \frac { nE }{ t } =\frac { 0.7nE' }{ t } \\ \frac { hc }{ λ } =\frac { 0.7hc }{ λ' } \\ \frac { λ' }{ λ } =0.7$$
 
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And the question is?
Oh and you are neglecting the work function of the metal- I think
 
Opps. I didn't realize the question was cut off.

Here's the second part:

Based on this information and the table given in the textbook, identify the metal.

Basically, what is required is to calculate the work function.

A: work function 2.23 eV. Potassium.
 
Turion said:
bump

Show your effort please. As suggested, did you take the work function into account? Retry the problem.
 
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