Photoelectric Effect - Wavelength of a Photon

AI Thread Summary
To calculate the wavelength of a photon with the same momentum as an electron moving at 1.0 x 10^6 m/s, the kinetic energy of the electron is first determined using the formula Ek = (m*v^2)/2. The momentum of the electron is then found, which is essential for relating it to the wavelength through the equation p = h/λ. The solution ultimately leads to a wavelength of 0.73 nm for the photon. Although the problem is situated in the photoelectric effect section, it primarily focuses on momentum and wavelength calculations. This highlights the interconnectedness of concepts in physics, despite the apparent topic mismatch.
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Homework Statement


Calculate the wavelength of a photon having the same momentum as an electron
moving at 1.0  106 m/s.
The answer is supposed to be 0.73 nm.

Homework Equations


Ek = (m*v^2)/2
Ek = hf - W
p = E/c = hf/c = h/\lambda


The Attempt at a Solution


I first found Ek using the kinetic energy formula, using the speed of the electron given in the question and the mass of the electron.
I can't quite figure out where to go next.
 
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This problem has nothing to do with the photoelectric effect. Find the momentum of an electron moving at the speed given, substitute it in p = h/λ, and solve for λ.
 
It is in the photoelectric effect section of the book, though.

Alright, thanks.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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