- #1
usfz28
- 19
- 0
My instructor was telling what would be on the upcoming test and he said something about:Given the velocity of an electron, the work function of a certain metal, and final energy level. We should be able to find the intial energy state. Sound pretty easy... to easy but here is what i was thinking...
Given the velocity of the electron, I can found out the kinetic energy of the electron 1/2MV^2=K.E.
With the K.E. I can then use f=((work funct)+(K.E.))/(H) to find the Freq. () With that I can then find λ=(C)/(F). to find λ the wavelength.
Then I finally can find the initial energy state by using:
N(initial)=Sq Root(((k(e)^2)/2(Aof zero)hc)-1/λ+n(final)^2))
Does that sound about right? Sorry about all the parenthesis :yuck:
Given the velocity of the electron, I can found out the kinetic energy of the electron 1/2MV^2=K.E.
With the K.E. I can then use f=((work funct)+(K.E.))/(H) to find the Freq. () With that I can then find λ=(C)/(F). to find λ the wavelength.
Then I finally can find the initial energy state by using:
N(initial)=Sq Root(((k(e)^2)/2(Aof zero)hc)-1/λ+n(final)^2))
Does that sound about right? Sorry about all the parenthesis :yuck: