Photons incident on the retina?

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The estimated number of photons incident on the eye per second from the night sky background is approximately 6*10^10. This figure raises questions about its validity, as the parameters used for the calculation were not provided. Without specific details on the light intensity and other relevant factors, it's difficult to assess the accuracy of the estimate. Clarification on the starting numbers is essential for a proper evaluation. Accurate calculations depend heavily on the initial parameters used in the estimation.
big man
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Sorry I just want to check that this is a reasonable estimate.

I calculated the amount of photons incident on the eye per second is about 6*10^10. This is from the night sky background and just seems way too much.
Sorry for such a stupid question.

thanks for any help
 
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There is no way to check if this is a "reasonable estimate" if you do not tell us the parameters that you started with. What are the numbers you used as the starting point such as the amount of light from the night time sky?

Zz.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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