Physical and analytical chemistry

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At 20 degrees Celsius, the solubility of solid substance x in water is 42g/L. Three solutions are discussed: S1 at 5.1g/L, S2 at 39g/L, and S3 at 57g/L. To saturate S1 with x, it is not sufficient to mix it with S2, as combining these dilute solutions will not yield a concentration above the solubility limit. Instead, S3 must be used to achieve saturation, as it exceeds the solubility threshold. The key takeaway is that mixing dilute solutions does not increase concentration beyond the solubility limit, and a more concentrated solution is necessary for saturation.
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at 20 degree celcius, the solubility of a solid substance x in water is 42g/L. There are 3 solutions containing x kept at this temperature: S1 5.1g/L, S2 contains 39g/L, and S3 contains 57g/L.

if we want to make S1 saturated with x, is it possible that we can add an equal volume of S2 and S1 because the overall concentration will become about 44g/L. or is it we must add more S2? what equation should I use?
 
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The answer is no. You cannot combine dilute solutions in any proportion to get a more concentrated one. You must use S3.
 
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