Physics 2 , two Styrofoam balls on insulated thread

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Homework Help Overview

The problem involves two small Styrofoam balls, each with a mass of 0.1 grams, that are charged and suspended on an insulating thread. The upper ball is free to move while the lower ball is fixed. The scenario requires determining the number of electrons added to each ball based on their repulsive forces and gravitational effects.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the forces acting on the upper ball, including gravitational force and electrostatic repulsion. There are attempts to equate these forces to find the charge on the balls. Questions arise about the correct interpretation of force values and units.

Discussion Status

The discussion is ongoing, with participants exploring the relationship between gravitational force and electrostatic force. Some guidance has been offered regarding the need to consider units and the correct application of force equations. There is no explicit consensus yet, as participants are clarifying misunderstandings and exploring different interpretations.

Contextual Notes

Participants are working under the assumption that the upper ball is in equilibrium, with the forces acting on it balanced. There is a focus on ensuring correct units and understanding the nature of gravitational force in relation to mass.

nathancurtis11
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Homework Statement


Two small .1 gram stryofoam balls are strung like beads on a vertical insulating thread. The lower ball is glued to the thread but the upper ball is free to move. Imagine that both are given an equal amount of negative charge such that the upper ball is suspended about the lower with their centers 4.0 cm apart. (Assume that each ball repels the other as if it were a point charge located at its center.) Roughly how many electrons have been added to each ball? Express your result as a fraction of the total number of electrons initially inside each ball.

Homework Equations



E = (kq1q2) / r^2

One electron = 1.6 x 10^-19 Coulombs

k = 9 X 10^ 9 N m^2 / c^2

The Attempt at a Solution



Assumed the force was now close to zero if the top ball is now suspended in the air instead of being pushed upward. But then you just get both charges to be zero which would be incorrect. Not sure any other way to do this.
 
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Don't forget gravity. The upper ball (that is free to move) is in a force equilibrium.
 
So would force be -9.81 then?? so -9.81 = (kq1q2) / r ^ 2 ?
 
A force is not a number, it has units.
What is the gravitational force on the styrofoam ball?
 
-9.81 Newtons.
 
so -9.81e-6 N c = ( 9e9 N m^2 / c ^2 (q^2) ) / ( .04m ^ 2)

solve for q from there?
 
nathancurtis11 said:
-9.81 Newtons.
How did you get this value? It is wrong.

Another issue: If you set those forces equal, they should have the same sign.
 
I thought since the ball was stationary then the force by the lower ball on the upper ball had to be exactly equal to the force by gravity, therefore would be the gravitational constant of 9.81
 
The gravitational constant is something different.
Check the equation for the gravitational force. And please do not forget units. They are exactly the right tool to avoid the mistakes you make.

In particular, do you expect all objects on Earth to have the same force? An elephant as much as a mouse? Do you see the issue?
 

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