Physics concept questions (electric field & potential diff.)

AI Thread Summary
The discussion centers on electric fields and potential differences in relation to charged plates. It is noted that while the electric field is typically considered constant for infinite plates, real plates with edges complicate this, leading to stronger fields near the edges. The relationship between electric potential (V), electric field (E), and distance (d) is highlighted, indicating that if V is constant and d decreases, E must increase. Participants emphasize the importance of treating the plates as infinite for simplification, while also acknowledging that the actual field may vary due to finite dimensions. Overall, the potential difference is expected to decrease as the distance between the plates decreases.
catch22
Messages
62
Reaction score
0

Homework Statement


upload_2015-11-10_18-58-59.png


Homework Equations

The Attempt at a Solution


1) charges should remain the same since there is no path for them to go anyway.
2) Now, if the panels were of infinite length, I believe the electric field should be the same regardless of distance? But in this case, the panels aren't infinitely long so there are sharp edges at each end and electric fields are stronger at sharp edges so I believe the answer should be : electric field increases.
3) using V=Ed , if d decreases and E increases... I have no idea then because it would depend on the magnitudes of d and E.
 
Physics news on Phys.org
#2)
upload_2015-11-10_19-15-12.png


____________________________________________________________________________________________________

#2a) the battery maintains the electric potential in each plate so the potential difference should remain the same.

#2b) using V = Ed, if V is constant, d is decreased, E should increase then.

#2c) I guess charges would remain the same since positive charges on the left plate would be require work to reach the positive terminal of the battery? and same goes for the left side.
 

Attachments

  • upload_2015-11-10_19-14-55.png
    upload_2015-11-10_19-14-55.png
    75.1 KB · Views: 371
upload_2015-11-10_19-37-24.png


__________________________________________________________________________________________________________________

Here is how I picture this:

upload_2015-11-10_19-37-56.png


using V=Ed, since V is constant, and the distance between the slab of metal and each plate is d/4, E should increase.
 
In respect of the first problem:
catch22 said:
if the panels were of infinite length, I believe the electric field should be the same regardless of distance? But in this case, the panels aren't infinitely long so there are sharp edges at each end and electric fields are stronger at sharp edges
I don't think you are supposed to worry about those details here. Treat the plates as infinite.
Yes, the field should not change. What does that tell you about potential difference?

Also, remember that the potential at any point is the sum of the potentials due to all the different charges. Consider the potential at one plate. As the other plate gets closer, will the potential there change?

For your other problems, please post each in a separate thread. Gets too confused otherwise.
 
haruspex said:
In respect of the first problem:

I don't think you are supposed to worry about those details here. Treat the plates as infinite.
Yes, the field should not change. What does that tell you about potential difference?

Also, remember that the potential at any point is the sum of the potentials due to all the different charges. Consider the potential at one plate. As the other plate gets closer, will the potential there change?

For your other problems, please post each in a separate thread. Gets too confused otherwise.
If the field doesn't change, then V should decrease as d decreases.

but why do we treat the plates as if they were infinitely long? say the plates are 1 meter long, each, would the field still remain the same?
 
catch22 said:
If the field doesn't change, then V should decrease as d decreases.

but why do we treat the plates as if they were infinitely long? say the plates are 1 meter long, each, would the field still remain the same?
Yes, The potential difference should decrease.
The plates are not infinitely long, so the field is a bit more complicated, but I see no reason why it should change the general trend of the answer. You are not given the relationship between the plate lengths and separation, so it is not possible to be more precise.
 
  • Like
Likes catch22
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top