Physics fields and chem combined question

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A standard 100W light bulb requires 120V, leading to a calculated current of approximately 0.8333 amps. A 5.0g copper penny contains around 4.68 x 10^21 electrons, which equates to a total charge of about 748.8 coulombs. Using the relationship Q = It, the time the light bulb could run on this charge is approximately 898.6 seconds, or about 15 minutes. This calculation is theoretical, as real-world energy transfer would likely reduce the actual runtime. The discussion emphasizes the integration of physics and chemistry principles to solve the problem.
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If a standard 100W light bulb needs 120V to shine, determine how long I could run the light bulb if I used up all the electrons in a copper penny to power it. Assume the penny to have a mass of 5.0g. Hint: think back to the units that make up watts and volts
 
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This is a wierd, non-physical question!

I assume they want you to figure out the current flowing through the bulb. Can you do that?

Once you have the current (I), then the total charge (Q) that flows per time (t) is: I = Q/t (that's the meaning of current).

To find the number of electrons in the penny: first find the number of copper atoms. (Hint: you'll need the atomic mass of copper) Then, depending on how wacky your teacher is, find the number of electrons: does he mean ALL electrons? or just the "free" electrons in the outer shell? I would use one electron per atom.

Then consider the charge on the electron. How many "electrons"/sec have to flow to make one Amp of current?
 


To answer this question, we need to use a combination of physics and chemistry concepts. First, let's start with the physics aspect of the question. Watts and volts are both units of power, with watts representing the rate at which energy is used and volts representing the amount of electric potential energy per unit charge. We can use the equation P = IV, where P is power, I is current (measured in amps), and V is voltage, to calculate the amount of power needed to run the light bulb.

In this case, we know that the light bulb needs 100W of power and 120V of voltage. So, using the equation, we can calculate the current needed to power the light bulb as I = P/V = 100W/120V = 0.8333 amps.

Now, let's move on to the chemistry aspect of the question. We are given the mass of a copper penny, which we can use to calculate the number of electrons it contains. Copper has an atomic mass of 63.5 g/mol and a molar mass of 6.022 x 10^23 electrons/mol. So, a 5.0g penny would contain approximately 4.68 x 10^21 electrons.

Next, we need to calculate the total charge of these electrons. Each electron has a charge of 1.6 x 10^-19 coulombs. So, the total charge in the penny would be 4.68 x 10^21 electrons x 1.6 x 10^-19 C/electron = 7.488 x 10^2 C.

Finally, we can use the equation Q = It, where Q is charge, I is current, and t is time, to calculate the time the light bulb could run using the charge in the penny. Plugging in the values we have calculated, we get t = Q/I = 7.488 x 10^2 C/0.8333 A = 898.6 seconds.

Therefore, using all the electrons in a copper penny, we could run the 100W light bulb for approximately 15 minutes (898.6 seconds) before depleting the charge in the penny. It is important to note that this is just a theoretical calculation and in reality, there would be losses in the transfer of energy, so the actual time may be slightly different.
 
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