What Is the Plane's Constant Acceleration During Takeoff?

AI Thread Summary
The discussion focuses on calculating an airplane's constant acceleration during takeoff, given the angle of a pocket watch and the time before the plane leaves the runway. Participants emphasize the relationship between the forces acting on the watch, including gravity and the acceleration of the plane, which can be analyzed using vector components. The challenge arises from the lack of mass information for the watch, but it is suggested to express forces in terms of an arbitrary mass variable. A specific example is provided, referencing a watch with a known mass to illustrate the calculation process. The conversation highlights the importance of understanding force dynamics in solving the problem.
asheik234
Messages
36
Reaction score
0

Homework Statement


An airplane begins its takeoff sequence moving with a constant acceleration a. A passenger holds up a pocketwatch during the takeoff sequence and notices that the watch makes an angle θ = 14° with the vertical, and that 13.3 seconds pass before the plane leaves the runway.

(a) What is the plane's constant acceleration?


(b) How far does the plane travel on the runway?


Homework Equations



F = ma

The Attempt at a Solution



There is no given mass, I don't know how to find it without it.
 
Physics news on Phys.org
The watch lanyard makes an angle determined by two perpendicular forces. One force is due to gravity acting on the watch's mass, m, the other due to acceleration of that same mass.
 
NascentOxygen said:
The watch lanyard makes an angle determined by two perpendicular forces. One force is due to gravity acting on the watch's mass, m, the other due to acceleration of that same mass.

Yes, but when you don't have the mass of the watch itself, how would you be able to solve it, all it gives you is the angle measure and the force of gravity, which is 10.

Here's a picture if it helps,

Frensley_Forces_Horizontal_006.gif
 
asheik234 said:
Yes, but when you don't have the mass of the watch itself, how would you be able to solve it,
Then you call its mass m kg, and work out the vector forces due to gravity and horizontal acceleration both in terms of m kg. What will the magnitudes of each force be?
 
asheik234 said:
Yes, but when you don't have the mass of the watch itself, how would you be able to solve it, all it gives you is the angle measure and the force of gravity, which is 10.

Here's a picture if it helps,

Frensley_Forces_Horizontal_006.gif

Don't forget that the person across the aisle, holding their watch up like you, will see their watch hang at the same angle, and their watch has a mass of precisely 0.21 kg. Does that help?
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top