Physics Help sound level intensity

AI Thread Summary
When one jet engine is shut down, the sound intensity level should decrease, as the total sound power is reduced. The initial calculation incorrectly suggests an increase to 125 dB, which contradicts the expected outcome. The correct approach involves using the ratio of intensities between three and two engines, which should yield a lower sound level. The logarithmic relationship indicates that the sound level should decrease by approximately 3 dB when one engine is turned off. Therefore, the new sound level with two engines would be around 117 dB.
smith22
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A person standing a certain distance from an airplane with three equally noisy jet engines is feeling a sound level intensity bordering on pain, 120dB. What sound level would this person experience if the captain shut down one engine?

this is what I did:
B-120=10log.33
and ended up with 125 dB as the intensity

What am I doing wrong since I am reducing the factor by 3 and its still not working?
 
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I see two problems:

(1) The sound level should be lower with only two engines running: log.33 is negative.

(2) You have the wrong ratio of intensities: What's the ratio of intensities for 3 engines versus 2 engines?
 
smith22 said:
A person standing a certain distance from an airplane with three equally noisy jet engines is feeling a sound level intensity bordering on pain, 120dB. What sound level would this person experience if the captain shut down one engine?

this is what I did:
B-120=10log.33
and ended up with 125 dB as the intensity

What am I doing wrong since I am reducing the factor by 3 and its still not working?
let I0 be ref sound intensity level
sound level (db) w/3 engines = 120 db = 10 log10( 3(I/I0) )
= 10 log10(3) + 10 log10( I/I0 )
= 10 log10(2*(3/2)) + 10 log10( I/I0 )
= 10 log10(3/2) + 10 log10(2) + 10 log10( I/I0 )
= 10 log10(3/2) + 10 log10( 2(I/I0) )
= 10 log10(3/2) + (sound level (db) w/2 engines)
 
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