- #1
Inv.e[ln(t*r)]=t
- 3
- 0
God, I took twenty minutes to prepare this, and then it logged me out when I tried to post it, and now I have to retype the whole damn thing. So here goes:
Here is the diagram: http://photobucket.com/albums/v517/shirozu/?action=view¤t=sharkproblem.jpg
Since its almost past ten, and I'm losing my coherency , I will make this really easy.
That diagram and problem requires me to find the sum of the torques. The torque that the cord performs on the rod, and the torque that the weight of the shark creates on the rod. First the shark:
I simplified the force by using a triangle. Through thinking, I eventually found that the angle inside of this triangle is 60 degrees. I am positive this is the right angle. So, I did the equation to find the torque:
cos(60)=x/10000
10000cos(60)=x
x=5000
the I came to the part where I actually find the torque, but in the equation it says to neglect the weight of the rod... do I just multiply 5000 by the length of the rod, which is given? If not, what do I do?
Also, finding the torque of the cord requires finding the tension. What exactly do I do here? I made the simplifying triangle, and eventually got to:
Tcos(10)=x
But what do I do? I have two variables, and the tension I don't think should be used if the length of the pole in the first torque equation is used. Its inconsistent, if you catch my drift.
Please help, I have a physics test on this tomorrow, and I have no one to ask except this forum. I would appreciate any help at all.
Thanks in advance.
Daniel
Here is the diagram: http://photobucket.com/albums/v517/shirozu/?action=view¤t=sharkproblem.jpg
Since its almost past ten, and I'm losing my coherency , I will make this really easy.
That diagram and problem requires me to find the sum of the torques. The torque that the cord performs on the rod, and the torque that the weight of the shark creates on the rod. First the shark:
I simplified the force by using a triangle. Through thinking, I eventually found that the angle inside of this triangle is 60 degrees. I am positive this is the right angle. So, I did the equation to find the torque:
cos(60)=x/10000
10000cos(60)=x
x=5000
the I came to the part where I actually find the torque, but in the equation it says to neglect the weight of the rod... do I just multiply 5000 by the length of the rod, which is given? If not, what do I do?
Also, finding the torque of the cord requires finding the tension. What exactly do I do here? I made the simplifying triangle, and eventually got to:
Tcos(10)=x
But what do I do? I have two variables, and the tension I don't think should be used if the length of the pole in the first torque equation is used. Its inconsistent, if you catch my drift.
Please help, I have a physics test on this tomorrow, and I have no one to ask except this forum. I would appreciate any help at all.
Thanks in advance.
Daniel