Physics homework problem - design a capacitor

AI Thread Summary
An engineer is tasked with designing a capacitor with a capacitance of 1 µF using a dielectric material with a constant of 260 and a dielectric strength of 8 MV/m. The maximum voltage the capacitor can handle is 160 volts, leading to the need for calculating the plate area. The formula A = 4πkdC is used, but the distance between the plates must be determined first using the relationship d = V/E. The initial attempt yielded an area of 0.113 m², but it was noted that the dielectric constant and dielectric strength were not utilized in the calculations. Proper incorporation of these values is crucial for an accurate design.
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Physics homework problem -- design a capacitor

Homework Statement


An engineer needs to design a capacitor with a capacitance of 1*10-6F using a material with a dielectric constant 260. If the dielectric strength of the material is 8*106 N/C, and the maximum voltage that the capacitor is allowed to handle is 160 volts, what must be the area of the plates?

Homework Equations


Q=CV, C=A/(4πkd)


The Attempt at a Solution



A=4πkdC; everything is known except the distance between plates

V=Ed, d=V/E; V is given

E=kq/r2, r=d

d=kq/V

A=4πk2CQ/V

I got A = .113m2 but I'm not sure If I'm doing it right or not. Could some check it for me please. I did not use the dielectric constant and dielectric strength values.

Thank you
 
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I did not use the dielectric constant and dielectric strength values.
Then you are doing it wrong.

What is important about the maximum voltage?
It is the voltage, above which, the capacitor does something special...
 
Dielectric strength can also be written as\frac{V}{m}, and Max Voltage on a capacitor is dielectric strength * distance between the plates.

Hope this helps.
 
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