Physics II forgotten equation (oscillations)

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Homework Help Overview

The discussion revolves around a formula related to oscillations, specifically concerning the velocity of an oscillating object derived from energy conservation principles. Participants are trying to clarify the origins and correctness of the equation v=w{\sqrt{A^2x^2}}.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants question the validity of the original equation based on unit analysis and discuss its derivation from the conservation of energy formula. There are attempts to manipulate the equation to find velocity, leading to different interpretations of the correct form.

Discussion Status

The discussion is active, with participants providing insights into the derivation process and questioning assumptions about the original equation. Some have offered alternative forms of the equation, suggesting a productive exploration of the topic.

Contextual Notes

There is mention of a test preparation context, and participants express confusion over the correctness of the equation and its derivation. The discussion includes references to specific terms and concepts related to oscillations and energy conservation.

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I am reviewing for a test on oscillations and I have no clue how I derived a formula I used for my homework.

Could anyone help me figure out where the equation [itex]v=w{\sqrt{A^2x^2}}[/itex] comes from? Thank you.
 
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That equation can't be correct. The units on the RHS work out to be length2/time.
 
vela said:
That equation can't be correct. The units on the RHS work out to be length2/time.

I actually just found the equation in the book, it comes from the conservations of energy formula. I don't understand how it can work for the same reason you listed, that's why I am confused. And I'm 100% sure I am copying it down correctly.

It is derived from:

[itex]\frac{1}{2}mv_x^2 + \frac{1}{2}kx^2=\frac{1}{2}kA^2[/itex]

[itex]mv_x^2 + kx^2=kA^2[/itex]
 
Try solving for the velocity.
 
vela said:
Try solving for the velocity.
You get [itex]v={\sqrt{{\frac{k}{m}}A^2x^2}}[/itex] which is equivolaent to [itex]v=w{\sqrt{A^2x^2}}[/itex].
 
No, you don't. How'd you get that?
 
vela said:
No, you don't. How'd you get that?

[itex]mv_x^2 + kx^2=kA^2[/itex]

Sorry, I'm not going to use latex for this so I can do it faster.

mv^2=kA^2-kx^2

v^2=(kA^2-kx^2)/m

v^2= (k/m)(A^2-x^2)

v=sqrt((w^2)(A^2-x^2))

v=w(sqrt(A^2-x^2))

I think that was actually beneficial for me typing that out lol.
 
Yup, that's the equation I think you were looking for.
 

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