Physics Kinematics: Larry's Peach

Thread starter lilwigz
Start date Jan 19, 2010
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Kinematics Physics

AI Thread Summary

Larry throws a peach upward from a height of 1.2m with an initial velocity of 3.2m/s, and the acceleration due to gravity is -9.81m/s². The relevant kinematic equation used to find the maximum height is Vf² = Vi² + 2a(delta x). Participants discuss the calculations needed to determine the maximum height the peach reaches. The solution involves calculating the final velocity at the peak and then using it to find the total height. The discussion emphasizes the application of kinematic equations in solving projectile motion problems.

Jan 19, 2010

lilwigz

Homework Statement

Larry throws a peach vertically upward from a height of 1.2m with an initial velocity of 3.2m/s. What is the maximum height the peach reaches?

Homework Equations

a= -9.81m/s^2

The Attempt at a Solution

I used the equation Vf^2=Vi^2+2a(delta x)

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Jan 19, 2010

rock.freak667

Homework Helper

lilwigz said:

The Attempt at a Solution

I used the equation Vf^2=Vi^2+2a(delta x)

And what did you get?

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