Physics Project Conservation of momentum,energy, and projectile motion

AI Thread Summary
The project involves using spring-loaded Nerf guns to analyze the conservation of momentum, energy, and projectile motion. The goal is to determine the spring constant and the bullet's acceleration before impact. Key calculations include finding the time for the bullet/target combo to reach the floor, resulting in a time of approximately 0.409 seconds, and calculating the initial velocity of the bullet/target combo as 0.935 m/s. Using conservation of momentum, the bullet's velocity before hitting the target is calculated to be 17.38 m/s. The project highlights the application of physics principles in a practical scenario.
Wilson_Serway
Messages
2
Reaction score
0
For my AP Physics Class we were given spring loaded nerf guns and asked to find a spring constant and the acceleration of the bullet before it hit the block. We had to hit a target that was on the edge of our desk and record the distance when the bullet stuck to the target. I have worked more than halfway through the problem, but have trouble when it comes to the conservation of energy and can't seem to find the acceleration.

Mb=.0136 kg
Mt=.2392 kg
X(Desk to landing place)=.3825 m
Y(Top of target to floor)=.82

To find time it takes for the bullet/target combo to reach the floor I used the y-component
Xy=XoY+Vo(t)+1/2(a)(t)2
0=.82+1/2(-9.81)(t)2
T=-.82/-4.905=.409

To find velocity of the bullet/target combo I substituted time into the x-component
X=Xo+Vo(t)+1/2(a)(t)2
.3852= Vo(.409)
Vo=.935

To find the velocity of the bullet before it hit the target I used the conservation of momentum
MbVb+ MtVt=( Mb+ Mt)Vo
.0136Vb+.2392(0)=(.0136+.2392).935
Vb=17.38
 
Last edited:
Physics news on Phys.org
Ohh I forgot the spring is compressed 0.06 meters and the distance from the tip of the gun to the block is 1.77 meters.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top