Pion decay in electron and neutrino

  • Thread starter mur79
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  • #1
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Main Question or Discussion Point

Hi,
I have a question about this decay: [tex]\pi^- \rightarrow e^- \overline{\nu_e}[/tex]
there is a factor:

[tex]1 - \frac{v_e}{c}[/tex]

what are these values, [tex]v_e,c[/tex], and why this quantity is equal to:

[tex]\frac{m^2_e}{m^2_\pi + m^2_e}[/tex]?

Thank you
Ciccio
 

Answers and Replies

  • #2
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Sorry but I don't understand why the latex don't work...

the decay is

pi- -> e- anti-nu(e)

the factor is: 1-v/c

and I don't understand what are v and c...
and why that quantity is equal to: (m_e)^2 / [(m_pi)^2 + (m_e)^2]

Thank you
Ciccio
 
  • #3
clem
Science Advisor
1,308
15
v is the electron velocity and c the speed of light.
In special relativity, v/c=pc/E, where p is the momentum and E the total energy.
Some more algebra is required to get the final result.
 

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