Pion's mean free path in a lake. exercIse question

Click For Summary

Homework Help Overview

The problem involves a charged pion with a specified average lifetime and mean free path, falling perpendicularly into a lake. Participants are tasked with determining the likelihood of the pion reaching the bottom of the lake based on its lifetime, velocity, and the mean free path in water.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculation of the effective height of the lake as perceived by the pion and the time required to reach the bottom. There is a focus on how to incorporate the mean free path into the analysis and the implications of the pion's lifetime relative to its travel time.

Discussion Status

Some participants question the original poster's conclusion about the pion not reaching the bottom, suggesting a need to consider both decay and interaction probabilities. There is an ongoing exploration of how to apply the mean free path in the context of the problem.

Contextual Notes

Participants note the average lifetime of the pion and the mean free path in water as critical factors in the discussion. There is an acknowledgment of the need to evaluate the probabilities of decay versus interaction with nuclei in the water.

tasos
Messages
9
Reaction score
0

Homework Statement


Charged pion with average life time $$\tau=10^{-8} sec$$, and mean free path in the water$$\ell=100m$$ falls prependicular to a lake (depth of lake is at $$\ell_0 =30m$$ with velocity $$V=0.9999c$$

What of the next is correct?

1). The particle isn't gona touch the bottom of the lake
2.)The particle have at least 60% probability to touch the lake
3.)The particle have a probability lower than 40% to touch the bottom of the lake

Homework Equations

The Attempt at a Solution



The first think i did is to calculate the Height of the lake "seen" by the pion
$$L=\ell_ 0 \sqrt{1+\frac{V^2}{c^2} } =0.42m$$

After that i calculate the time needs to touch the bottom of the lake

$$t=\frac{L}{V} =0.14 \times 10^{-8} $$

So if pion's life time is $$\tau=10^-8 sec$$ and it needs $$t=0.14 \times 10^{-8} $$, i say that it not gona touch the bottom of the lake.

BUT the excersice is giving me also the mean free path in the water$$\ell=100m$$
and i don't know how to use it, or if i need to use it.

Any sugestions? Thanx a lot.
 
Physics news on Phys.org
I'm not able to help with particle physics, but ...

just looking at your conclusion, I can't see how you could arrive at it. The particle has a mean lifetime of 10-8 s, and you say it would require just ##\frac 1 7## of this duration to traverse the lake's depth.

How do you conclude it probably won't reach the lake bed?
 
in pion's system from this results we conclude that is going to decay before it reach the bottom. This 1/7 you say its the problem. But given the average free path in the water ,i think i need to calculate some probability.
For example if i had a beam with $$N_0$$ pions, given the average path we no that $$N=N_0 e^{-\frac{t}{\tau}} $$ so we can see how many particles will survive for a given time t.
The same equation is for the path $$N=N_0 e^{-\frac{L}{\ell}}$$
 
tasos said:
in pion's system from this results we conclude that is going to decay before it reach the bottom.
Why? The flight time in the pion system is just 1/7 of its lifetime. Why do you expect all pions to decay so early?

Pions can decay or hit a nucleus in the water, in both cases the pion is not there any more. You'll have to check how likely both cases are to see if the pion makes it to the bottom.
 

Similar threads

Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
3
Views
1K
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
6K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 3 ·
Replies
3
Views
6K
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
9K
  • · Replies 12 ·
Replies
12
Views
6K