How Long Does a Plane Have to Escape After Tossing a Bomb Upward?

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The discussion revolves around a physics problem involving a plane releasing a bomb at a steep angle while climbing. The plane's speed is 600 km/hr, and the bomb is released from an altitude of 4000 m, set to detonate at 500 m above the ground. Participants suggest using trigonometry to break down the initial velocity into horizontal and vertical components, applying kinematic equations to solve for the time before detonation, maximum height, and speed at detonation. The original poster expresses frustration with the problem and seeks guidance, indicating a need for step-by-step assistance. The conversation emphasizes the importance of understanding projectile motion principles to tackle similar problems effectively.
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Plane with an exploding bomb--PLEASE HELP ME!

Homework Statement


The early technique for dropping a plane bomb was to not "drop" but to let it go as the plane was climbing at a rapid rate. The idea "toss" it upward at a steep angle therefore giving the plane enough time to turn away before the bomb exploded.
Assume the plane is traveling 600 km/hr and it releases the bomb at an angle of 75 degrees above the horizontal. Assume the plane releases the bomb at an altitude of 4000 m above the ground and the bomb is set to detonate at 5r00 m above the ground. Ignoring air resistance, a) how long does the plan have to get away before the bomb exploding
b) what max height above ground level does the bomb reach? c) what is the bomb's speed as it detonates?


Homework Equations


plane is flying at 600 km/hr ----> 600,000 m /hr
altitude from ground up is 4000m
explodes at 500 m


The Attempt at a Solution


i really don't know what to do this. my book only has two problems similar to this and both involve wind speeds/resistance so i can't make any comparisons.

Please guide me through! i would REALLY appreciate it!
 
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This appears to be a typical baseball problem - you know the initial speed and angle.
The usual routine on these is to make two headings, for horizontal and vertical motion.
You must use trigonometry to separate the initial speed into horiz and vertical parts.
Then under the horizontal heading, use d = vt because there is no acceleration.
Under vertical, use V = Vo + at and d = Vot + .5at^2.
Put your numbers in and hopefully you will be able to find something with one of the three formulas!
 


how do i recognize what is each variable?
initial velocity is 600km/h?
time we don't know
a=g (9.80)
what is V?
 


"initial velocity is 600km/h?" must be converted into meters/second.
Then split into horizontal and vertical components using trigonometry.
Sketch an arrow 75 degrees above horizontal. Then draw a horizontal line from the beginning, drop a vertical line from the end to form a triangle. Find the horizontal and vertical sides of the triangle.
 


ok-i tried as hard as i could but I am still stuck.
can you just show me how to do this? I am ready to give up! :(
(by the way-i have another problem that is verry similar to this one-so if you help me out then i can do the other one as well!)

thanks!
 


http://hypertextbook.com/physics/mechanics/projectiles/

Check out that link for an introduction to equations of projectiles
 
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