Planet Orbits, finding radius HELPP

AI Thread Summary
To find the average radius of Mars' orbit around the sun, the gravitational force and centripetal force equations are utilized. The mass of Mars is 6.418 x 10^23 kg, and the sun's mass is 1.99 x 10^30 kg, with Mars completing its orbit in 687 days. The velocity of Mars can be expressed using the orbital period, leading to the equation G*M*T^2 = 4*pi^2*r^3 for radius r. After substituting the values and converting days to seconds, the calculated radius appears excessively large, prompting further verification of the calculations. Accurate application of these formulas is essential for determining the correct orbital radius.
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Planet Orbits, finding radius HELPP!

Homework Statement


The planet Mars has a mass of 6.418*1023kg and completes an orbit around the sun in 687 days. The sun has a mass of 1.99 * 1030kg. what is the average radius of the orbit of mars?


Homework Equations


Force Gravity = G*(m1m2)/r2
Force Centripital = mv2/r

G = 6.67 * 10-11


The Attempt at a Solution


I tried plugging in the numbers into the Universal gravitaiton formula where m1 was the mass of Mars * m2 which is the mass of the sun * Universal gravitation. I didn't know what to use as Force Gravity.
with the force centripital formula, you have 2 masses. how could i go about finding the velocity of Mars if i don't have the radius??
thanks for the help
 
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G*M*m/r^2 = m*v^2/r. Or
G*M/r= v^2...(1)
In the problem time T to completes an orbit around the sun is given.
So velocity v = 2*pi*r/T...(2)
Substitute the expression of v in eq.1 and solve for r.
 


for when i plug in equation 1, would i take the square root of the whole left side??
 


G*M/r= v^2...(1)
G*M/r= (2*pi*r/T)^2...(2)
If you simplify, you get
G*M*T^2= 4*pi^2*r^3.
Convert days to seconds and solve for r.
 


I got an answer with over a billion km lol seems kinda big even for planets but whatever

thanks alot
 
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