- #1
darryw
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Homework Statement
(y-x^3) + (x+y^3)y' = 0
equation is convenienty already in the required form, that is M_(x,y) + N_x(x,y)dy/dx = 0
so..
M_y = 1 = N_x therefore equation is exact. Therefore I now solve...
I am solving for a function, f(x,y) whose partial derivative with respect to y = M
and whose partial with respect to x = N.
Is this correct?
assuming correct so far, my next step is to integrate the M term, with respect to x
integ M_x (y-x^3) = -(1/4)x^4 + h(y)
i have a questions about this step though:
if y's are treated as constants when integrating, wouldn't the y in this equation become yx?
so that integ_x (y-x^3) = yx -(1/4)x^4 + h(y)
??
assuming yx is not in the integrated result, my next step is to take derivative of the just integrated M term, now with respect to y:
derivative of just-integ M_y [-(1/4)x^4 + h(y) ] = h'(y)
so i know that h'(y) = N term which is:
h'(y) = (x+y^3)
But i think I am going to stop here because it looks sort of weird and i want to make sure its right so far.
thanks for any help