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The calculation for the change in potential energy of a 2.50 kg textbook lowered from 1.81 m to 1.50 m is correct, resulting in -7.595 Joules. The negative sign indicates a loss of potential energy, which is an important detail. To enhance clarity, it's recommended to include units in the final submission. Overall, the numbers used in the calculation are accurate. Providing additional context or explanation before submission would improve the presentation.
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3. You lower a 2.50 kg textbook (remember when textbooks used to be made out of paper instead of being digital?) from a height of 1.81 m to 1.50 m. What is its change in potential energy?

1.50-1.81=-.31
(2.50kg)(9.80)(-.31)

=-7.595?
 
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Ion1776 said:
3. You lower a 2.50 kg textbook (remember when textbooks used to be made out of paper instead of being digital?) from a height of 1.81 m to 1.50 m. What is its change in potential energy?

1.50-1.81=-.31
(2.50kg)(9.80)(-.31)

=-7.595?

Looks good. It is particularly good that you have minus sign, indicating that the book has lost potential energy. To be perfect, give the units.
 
The numbers are OK. I'd put in some units and some text before you turn it in.
 
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