Please Plese Help Me -physics Problem -

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The discussion revolves around a physics problem involving a collision between two masses, m and 2m, where mass m strikes mass 2m at rest and is deflected at a 45-degree angle with a reduced speed. Participants suggest using the principle of conservation of momentum to solve the problem. There is a reminder about forum guidelines requiring users to attempt a solution before seeking help. Additionally, it is noted that the original poster has already made an attempt, which is referenced in another thread. The conversation emphasizes the importance of following forum rules while addressing physics problems.
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Please Plese Help Me --physics Problem --

A mass, m, traveling at a speed v, strikes another mass = 2m at rest. After the collision, the first mass, m, is delfected through 45 degrees and has a final speed of v/2.
Find the speed and Direction of the mass 2m after this collision.

thank you
 
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I think this should be in the Homework & Coursework Questions section.Well i think,the problem can be solved using the prinicple of conservation of momentum
 
It is over there too.
 
Yes. Moreover our policy requires you to give an attempt at solution before we help... (read the guidelines).
 
vanesch said:
Yes. Moreover our policy requires you to give an attempt at solution before we help... (read the guidelines).

He did, there is already a thread over here with the attempt.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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Thread 'Struggle to understand the concept of the question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
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