Finding Coordinates of Point P in Quadrant 2 with sin(-)=m

UP in the Y direction. So sin theta = Y/1.In summary, point P is the intersection of the terminal arm of angle (-) in standard position and the unit circle with centre (0, 0). P is located in quadrant 2 and the sine of angle (-) is represented by m. To determine the coordinates of P in terms of m, we use the definition of sine and cosine in a unit circle, where sine is equal to the ratio of the opposite side to the hypotenuse and cosine is equal to the ratio of the adjacent side to the hypotenuse. Since the unit circle has a radius of 1, the coordinates of P will be (m, ?m), with the y
  • #1
FalconF1
4
0

Homework Statement


Point P is the intersection of the terminal arm of angle (-) in standard position and the unit circle with centre (0, 0). If P is in quadrant 2 and sin (-)= m, determine the coordinates of P in terms of m.


Homework Equations





The Attempt at a Solution


no idea
 
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  • #2


This is a lovely example of the special properties of the unit circle. The first thing you should do though with a problem like this is draw a picture.

http://img24.imageshack.us/my.php?image=tempw.jpg
 
  • #4


FalconF1, what is the definition of [tex]sin \theta[/tex] and [tex]cos \theta[/tex] in a unit circle?


01
 
  • #5


The definition of sin theta in any case is opposite/hypotenuse and cos theta is adjecent/hypotenuse. The unit circle has a radius of 1 so any right triangle with vertices at the origin, a point P on the circle, and the X or Y axis ( is a purely your choice, most choose the X axis ) will have a hypotenuse of 1. So if you chose to drop to the X axis then sin theta = Y/1 and cos theta = X/1.
 
  • #6


My teacher used to say that the easiest way to remember sin theta is Y sin
 
Last edited:

1. What is the formula for finding the coordinates of point P in Quadrant 2 with sin(-)=m?

The formula for finding the coordinates of point P in Quadrant 2 with sin(-)=m is (m, -√(1-m²)).

2. How do you determine the value of m when finding the coordinates of point P in Quadrant 2?

The value of m can be determined by taking the inverse sine (arcsine) of the given angle, which is equivalent to the y-coordinate of point P.

3. Can the coordinates of point P in Quadrant 2 be negative?

Yes, the coordinates of point P in Quadrant 2 can be negative because the y-coordinate is always negative in this quadrant.

4. Is there a difference in finding coordinates in Quadrant 2 compared to other quadrants?

Yes, there is a difference in finding coordinates in Quadrant 2 compared to other quadrants because the x-coordinate in this quadrant is always positive, while the y-coordinate is always negative.

5. How can the coordinates of point P in Quadrant 2 be used in real-world applications?

The coordinates of point P in Quadrant 2 can be used in real-world applications such as navigation, astronomy, and physics to determine the position and direction of objects.

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