- #1

ChiralSuperfields

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- 132

- Homework Statement
- Please see below

- Relevant Equations
- Please see below

EDIT: For this part(b) of this problem,

The solution is

However, isn't there more points of inflection than just ##t = 3,5 s ##? Points of inflection is when ##x'' = a = 0## so it should be ## 3 ≤ t ≤ 5 s##

I also have a question about part(d):

The solution is

However, could I tried solving for the position by finding the area under the velocity curve from t = 0 to t = 6 sec.

## 0.5 \times 3 \times 8 + 2 \times 8 + 1\times 4 + 1 \times 1 \times 4 = 34 m ##.

I don't understand what I have done wrong since I should be able to get the correct answer from areas.

Can someone please help?

Many thanks!

The solution is

However, isn't there more points of inflection than just ##t = 3,5 s ##? Points of inflection is when ##x'' = a = 0## so it should be ## 3 ≤ t ≤ 5 s##

I also have a question about part(d):

The solution is

However, could I tried solving for the position by finding the area under the velocity curve from t = 0 to t = 6 sec.

## 0.5 \times 3 \times 8 + 2 \times 8 + 1\times 4 + 1 \times 1 \times 4 = 34 m ##.

I don't understand what I have done wrong since I should be able to get the correct answer from areas.

Can someone please help?

Many thanks!

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