Pointwise Convergence in Metric Space (C[a,b],d_{\infty}) | Homework Solution

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Homework Statement



Suppose a sequence (f_n)_{n\in\mathbb{N}} converges to a limit f in the metric space (C[a,b],d_{\infty}) (continuous real valued functions on the interval [a,b] with the uniform metric.)

Show that f_n also converges pointwise to f; that is for each t\in [a,b] we have f_n(t)\to f(t) in \mathbb{R}.

Homework Equations



Uniform metric: d_{\infty} (f,g) = \text{max}_{t\in [a,b]} |f(t)-g(t)|

The Attempt at a Solution



f_n \to f in (C[a,b],d_{\infty}) \iff d_{\infty}(f_n,f)\to 0

\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\, \iff \text{max}_{t\in [a,b]} |f_n(t)-f(t)| \to 0

\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\, \iff|f_n(t)-f(t)| \to 0 for all t\in [a,b]

\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\, \iff f_n(t) \to f(t) for all t\in [a,b]

Does this prove it?
 
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Looks ok to me.
 
Ted123 said:

Homework Statement



Suppose a sequence (f_n)_{n\in\mathbb{N}} converges to a limit f in the metric space (C[a,b],d_{\infty}) (continuous real valued functions on the interval [a,b] with the uniform metric.)

Show that f_n also converges pointwise to f; that is for each t\in [a,b] we have f_n(t)\to f(t) in \mathbb{R}.

Homework Equations



Uniform metric: d_{\infty} (f,g) = \text{max}_{t\in [a,b]} |f(t)-g(t)|

The Attempt at a Solution



f_n \to f in (C[a,b],d_{\infty}) \iff d_{\infty}(f_n,f)\to 0

\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\, \iff \text{max}_{t\in [a,b]} |f_n(t)-f(t)| \to 0

\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\, \iff|f_n(t)-f(t)| \to 0 for all t\in [a,b]

\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\, \iff f_n(t) \to f(t) for all t\in [a,b]

Does this prove it?

You need to be careful what you are proving. You have all these \iff implications which would lead one to believe that pointwise convergence and uniform convergence are the same. But they aren't. So look at your argument carefully and make sure the implications go in the direction to prove what you want to prove.
 
LCKurtz said:
You need to be careful what you are proving. You have all these \iff implications which would lead one to believe that pointwise convergence and uniform convergence are the same. But they aren't. So look at your argument carefully and make sure the implications go in the direction to prove what you want to prove.

Good point!
 
Obviously to prove what I want I only need all steps to be \implies but which step above is not "if and only if"? (is it the last step?)
 
|f_n(t)-f(t)|->0 for all t does not imply max |f_n(t)-f(t)|->0. Can you think of a counterexample?
 
Ted123 said:
Obviously to prove what I want I only need all steps to be \implies but which step above is not "if and only if"? (is it the last step?)

Dick said:
|f_n(t)-f(t)|->0 for all t does not imply max |f_n(t)-f(t)|->0. Can you think of a counterexample?

And I would add that if I were handing in a proof, I would use a tighter argument. While your implications in one direction are OK, you wouldn't have made that mistake if your argument went something like:

0 \le |f_n(t)-f(t)| \le ... \rightarrow 0

where you fill in the dots with reasons for each step.
 

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