Poisson Distrib.: Estimating Mean of Data Set

AI Thread Summary
To estimate the mean of a data set from a Poisson distribution, one can calculate both the arithmetic average and fit the data to a Poissonian model. The choice between these methods may yield different results, and the best estimator depends on the context of the analysis. It's important to consider whether the estimation method produces an unbiased result, as well as the implications of overestimating versus underestimating the mean. A comprehensive solution may involve a cost function and Bayesian analysis to determine the most appropriate approach. Understanding the specific context of the exercise is crucial for accurate estimation.
aaaa202
Messages
1,144
Reaction score
2

Homework Statement


I am given a data set known to come from a poisson distribution.

Homework Equations


Poisson distribution

The Attempt at a Solution


I want to calculate the mean of the data set for use in the Poisson Distribution function. How do I best estimate this. Do I take the arithmetic average of the data set or do I fit to a Poissonian? Which is the better estimator for the true mean?
 
Physics news on Phys.org
well, why not do both and compare the results ? There is a small subtle difference, but it may go unnoticed in many cases.
 
I just want to know which is closer to the correct result, i.e. the parameter for the true distribution.
 
You've been around long enough to know PF requires an effort from your side too. What is the exact problem formulation ?
What is the context of the exercise (intro, hypothesis testing, chi-squared, other?)
You are supposed to have sufficient knowledge of the matter at hand to do this exercise -- so if this is just additional curiosity, do the exercise first. And if it's part of the exercise, then an attempt at solution is required by PF rules before assistance can be given.
 
aaaa202 said:
I just want to know which is closer to the correct result, i.e. the parameter for the true distribution.
That's not an answerable question. Sometimes one will be closer, sometimes the other. What you can ask is which produces an unbiased result, i.e. no consistent tendency to underestimate or overestimate.
Even then, this might not be the best in practice. It depends what you will do with the answer. In some contexts, it may be much more costly to overestimate than to underestimate, say. A full solution involves a cost function, and, no doubt, Bayesian analysis.
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks

Similar threads

Replies
2
Views
2K
Replies
1
Views
2K
Replies
19
Views
13K
Replies
6
Views
3K
Replies
4
Views
3K
Replies
2
Views
1K
Back
Top