Polar coordinate to compute the volume

DrunkApple
Messages
110
Reaction score
0

Homework Statement


Use polar coordinates to compute the volume of the region defined by
4 - x^{2} - y^{2} ≤ z ≤ 10 - 4x^{2} - 4y^{2}


Homework Equations





The Attempt at a Solution


I got z = 2 so set up the equation

V = f^{2pi}_{0}f^{5/2}_{2}f^{0}_{2}r*dzdrdθ

is the domain correct?
 
Physics news on Phys.org
DrunkApple said:

Homework Statement


Use polar coordinates to compute the volume of the region defined by
4 - x^{2} - y^{2} ≤ z ≤ 10 - 4x^{2} - 4y^{2}

Homework Equations


The Attempt at a Solution


I got z = 2 so set up the equation

V = f^{2pi}_{0}f^{5/2}_{2}f^{0}_{2}r*dzdrdθ

is the domain correct?
Those are cylindrical coordinates, not polar. (If you were to do the problem in cylindrical coords, your limits of integration for z would be incorrect.)

The two surfaces intersect at z=2, but that's not particularly important. At what value of r do they intersect?
 
setting 4 - x^{2} - y^{2} and 10 - 4x^{2} - 4y^{2} to equal, r = ±√2, but since r must be greater than 0, it's r = √2
 
The volume element is the area element, r dr dθ, times the height, which you get from zupper - zlower .

z goes from 4 - r2 to 10 - 4r2 .
 
thank you I got it.
But how do I know if it's cylindrical?
 
How do you know if what is cylindrical? If you mean the coordinate system, "cylindrical coordinates" are just polar coordinates for the xy-plane with the z coordinate.
 
I mean just by looking at the equation
Is it because it contains z?
 
DrunkApple said:
thank you I got it.
But how do I know if it's cylindrical?
If you're asking how did I know you were using cylindrical coordinates rather than polar; cylindrical coordinates are in 3 dimensions and use r, θ, and z. Polar coordinates are 2 dimensional using r and θ.
 
Back
Top